0.25x^2-4=0

Solution for 0.25x^2-4=0 equation:

0.25x^2-4=0

a = 0.25; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·0.25·(-4)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2}{2*0.25}=\frac{-2}{0.5}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2}{2*0.25}=\frac{2}{0.5}
=4
$